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Mcqs

Class 12 Maths Mcqs

Our 1000+ multiple choice questions and answers (MCQs) on "Mathematics - Class 12" (along with 1000+ MCQs on "Mathematics - Class 11") focus on all areas of Mathematics covering 200+ topics. One can read MCQs on Mathematics Class - 11. These topics are chosen from a collection of the most authoritative and best reference books on Mathematics. One should spend 1 hour daily practicing these MCQs for 2-3 months to learn and assimilate the Mathematics subjects comprehensively. This way of systematic learning will prepare anyone easily for Mathematics - Class 12 exams, contests, online tests, quizzes, MCQ-tests, viva-voce, interviews, and certifications.

 

Mathematics - Class 12 Multiple Choice Questions Highlights

  • 1000+ Multiple Choice Questions & Answers (MCQs) in Mathematics - Class 12 with a detailed explanation of every question.
  • These MCQs are organized chapterwise and each Chapter is further organized topicwise.
  • Every MCQ set focuses on a specific topic of a given Chapter in Mathematics - Class 12 Subject.
  • Class 12 Mathematics MCQ with answers in PDF format for all chapters based on the CBSE, ICSE, and NCERT Pattern.

 

Who should Practice Mathematics - Class 12 MCQs?

  • Students who are preparing for various school tests such as unit-tests, term-tests, semester tests, half-yearly and yearly tests, and examinations on Mathematics - Class 12.
  • Students who are preparing for Online/Offline Tests/Contests in Mathematics for class 12.
  • Students who wish to sharpen their knowledge of Mathematics.
  • Students who are studying in CBSE, ICSE, IGCSE schools as well as various State Board schools.
  • Students who are preparing for competitive examinations such as NTSE, Olympiad, etc for class 12.
  • Students who are preparing for Central board examinations in Mathematics namely CBSE, ICSE, and NIOS Board.
  • Students who are preparing for State board examinations in Mathematics such as PUC, Intermediate exams, etc.
  • Students who are preparing for engineering entrance examinations like IIT JEE, AIEEE & SAT Exams in Mathematics.

 

Mathematics - Class 12 Chapters

Here's the list of chapters on the "Mathematics - Class 12" subject covering 100+ topics.

  • Maths Class 12 MCQ Chapter 1: Relations and Functions
  • Maths Class 12 MCQ Chapter 2: Inverse Trigonometric Functions
  • Maths Class 12 MCQ Chapter 3: Matrices
  • Maths Class 12 MCQ Chapter 4: Determinants
  • Maths Class 12 MCQ Chapter 5: Continuity and Differentiability
  • Maths Class 12 MCQ Chapter 6: Application of Derivatives
  • Maths Class 12 MCQ Chapter 7: Integrals
  • Maths Class 12 MCQ Chapter 8: Application of Integrals
  • Maths Class 12 MCQ Chapter 9: Differential Equations
  • Maths Class 12 MCQ Chapter 10: Vector Algebra
  • Maths Class 12 MCQ Chapter 11: Three Dimensional Geometry
  • Maths Class 12 MCQ Chapter 12: Linear Programming
  • Maths Class 12 MCQ Chapter 13: Probability
  • Maths Class 12 MCQ Chapter 14: Application of Calculus

 

Latest Popular
Q:

A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct² (a, b > 0). What is the meaning of the constant b?

A) Final velocity B) Initial velocity
C) Mid velocity D) Arbitrary velocity
 
Answer & Explanation Answer: B) Initial velocity

Explanation: We have, x = a + bt + ct²? ……….(1)
Let, v and f be the velocity and acceleration of a particle at time t seconds.
Then, v = dx/dt = d(a + bt + ct²)/dt = b + ct ? ……….(2)
Now from (2) we get v = b, when t = 0.
Hence b represents the initial velocity of the particle.

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Category: School MCQs
Sub Category: Class 12 Maths Mcqs

25
Q:

A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct² (a, b > 0). What is the meaning of the constant a?

A) Initial position B) Final position
C) Mid position D) Any arbitrary position
 
Answer & Explanation Answer: A) Initial position

Explanation: We have, x = a + bt + ct² ?……….(1)
Now from (1) we get x = a, when t = 0.
This means that the distance of the particle from O at time t = 0 is a ft.
Thus, a represents the initial position of the particle.

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Sub Category: Class 12 Maths Mcqs

76
Q:

“It is impossible for a particle to move in a straight line so that its velocity varies at the distance from the commencement of motion”. Which one is correct for the given statement?

A) The above statement is valid B) The above statement is not valid
C) Data inadequate D) Answer does not exist
 
Answer & Explanation Answer: A) The above statement is valid

Explanation: Let a particle be moving along the straight-line OX and P be its position at time t, when OP = x. Clearly, the velocity and acceleration of the particle at P are dx/dt and d²x/dt² respectively.
If possible, let us assume,
dx/dt ? x
dx/dt = kx, where k is a constant variation.
Now, d²x/dt² = d(kx)/dt = k(dx/dt)
= k²x
At the starting point O, we have x = 0 and we see that dx/dt = 0 and d²x/dt² = 0, when x = 0 that is, both velocity and acceleration of the particle are zero at x = 0 and the particle remains at rest at O.
Therefore, it is impossible for a particle to have any motion under the given condition.

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Sub Category: Class 12 Maths Mcqs

45
Q:

A particle is moving along the straight line OX and its distance x is in metres from O after t seconds from start is given by x = t³ – t² – 5t. What will be the distance traversed before it comes to rest?

A) -173/27 B) 173/27
C) -175/27 D) 175/27
 
Answer & Explanation Answer: C) -175/27

Explanation: We have, x = t³ – t² – 5t ……….(1)
When x = 28, then from (1) we get,
t³ – t² – 5t = 28
Or t³ – t² – 5t – 28 = 0
Or (t – 4)(t² + 3t + 7) = 0
Thus, t = 4
Let v and f be the velocity and acceleration respectively of the particle at time t seconds. Then,
v = dx/dt = d(t³ – t² – 5t)/dt
= 3t² – 2t – 5
And f = dv/dt = d(3t² – 2t – 5)/dt
= 6t – 2
Again the particle comes to rest when v = 0
Or 3t² – 2t – 5 = 0
Or (3t – 5)(t + 1) = 0
Or t = 5/3, -1
As, t > 0, so, t = 5/3
Therefore, the distance traversed by the particle before it comes to rest
= [(5/3)³ – (5/3)² – 5(5/3)] m ? [putting t = 5/3 in (1)]
= -175/27

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Category: School MCQs
Sub Category: Class 12 Maths Mcqs

31
Q:

A particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t³ – 12t + 11. What is the displacement of the particle at the end of 2 seconds?

A) 1 cm B) 2 cm
C) 3 cm D) 4 cm
 
Answer & Explanation Answer: C) 3 cm

Explanation: We have, x = 2t³ – 12t + 11 ……….(1)
Putting t = 2 in (1), we get,
Displacement = x = 2t³ – 12t + 11
= 2(2)³ – 12(2) + 11
= 3 cm.

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Category: School MCQs
Sub Category: Class 12 Maths Mcqs

29
Q:

A particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t³ – 12t + 11. What is the velocity of the particle at the end of 2 seconds?

A) 10 cm/sec B) 12 cm/sec
C) 14 cm/sec D) 16 cm/sec
 
Answer & Explanation Answer: B) 12 cm/sec

Explanation: We have, x = 2t³ – 12t + 11 ……….(1)
Let v and f be the velocity and acceleration respectively of the particle at time t seconds.
Then, v = dx/dt = d(2t³ – 12t + 11)/dt
= 6t² – 12 ……….(2)
Putting the value of t = 2 in (2),
Therefore, the displacement of the particle at the end of 2 seconds,
6t² – 12 = 6(2)² – 12
= 12 cm/sec.

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Category: School MCQs
Sub Category: Class 12 Maths Mcqs

37
Q:

A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t – 15t² + 4t³. What will be the distance between the two positions of the particle at two times, when the velocity is instantaneously 0?

A) 27/4 cm B) 29/4 cm
C) 27/2 cm D) 29/2 cm
 
Answer & Explanation Answer: A) 27/4 cm

Explanation: We have, s = 12t – 15t² + 4t³ ……….(1)
Differentiating both side of (1) with respect to t we get,
(ds/dt) = 12 – 30t + 12t²
Clearly, the velocity is instantaneously zero, when
(ds/dt) = 12 – 30t + 12t² = 0
Or 12 – 30t + 12t2 = 0
Or (2t – 1)(t – 2) = 0
Thus, t = 2 or t = ½
Putting the value t = 2 and t = ½ in (1),
We get, when t = 2 then s = (s1) = 12(2) – 15(2)² + 4(2)³ = -4.
When t = ½ we get, s = (s2) = 12(1/2) – 15(1/2)² + 4(1/2)³ = 11/4.
Thus, the distance between the two positions of the particle at two times, when the velocity is instantaneously 0 = s2 – s1
= 11/4 – (-4)
= 27/4 cm.

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Category: School MCQs
Sub Category: Class 12 Maths Mcqs

37
Q:

A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t – 15t² + 4t³. What is the velocity of the particle after 3 seconds?

A) 10 cm/sec B) 20 cm/sec
C) 30 cm/sec D) 40 cm/sec
 
Answer & Explanation Answer: C) 30 cm/sec

Explanation: Not available for this question

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